1/x+2/5=2/2x

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Solution for 1/x+2/5=2/2x equation: 



1/x+2/5=2/2x

We move all terms to the left:

1/x+2/5-(2/2x)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

1/x-(+2/2x)+2/5=0

We get rid of parentheses

1/x-2/2x+2/5=0

We calculate fractions


8x^2/50x^2+50x/50x^2+(-50x)/50x^2=0

We multiply all the terms by the denominator


8x^2+50x+(-50x)=0

We get rid of parentheses

8x^2+50x-50x=0

We add all the numbers together, and all the variables

8x^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{16}=0$

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