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1/x+2/9x=-3
We move all terms to the left:
1/x+2/9x-(-3)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 9x!=0We add all the numbers together, and all the variables
x!=0/9
x!=0
x∈R
1/x+2/9x+3=0
We calculate fractions
9x/9x^2+2x/9x^2+3=0
We multiply all the terms by the denominator
9x+2x+3*9x^2=0
We add all the numbers together, and all the variables
11x+3*9x^2=0
Wy multiply elements
27x^2+11x=0
a = 27; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·27·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*27}=\frac{-22}{54} =-11/27 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*27}=\frac{0}{54} =0 $
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