1/x+2=x+5/x

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Solution for 1/x+2=x+5/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x+2 = x+5/x // - x+5/x

1/x-x-(5/x)+2 = 0

1/x-x-5*x^-1+2 = 0

2*x^0-1*x^1-4*x^-1 = 0

(2*x^1-1*x^2-4*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^1-1*x^2-4*x^0) = 0

x^1

2*x-x^2-4 = 0

2*x-x^2-4 = 0

DELTA = 2^2-(-4*(-1)*4)

DELTA = -12

DELTA < 0

x in { } 

x belongs to the empty set

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