1/x+3/2x-x-2/4x=10

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Solution for 1/x+3/2x-x-2/4x=10 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(3/2)*x-x-((2/4)*x)+1/x = 10 // - 10

(3/2)*x-x-((2/4)*x)+1/x-10 = 0

(3/2)*x-x+(-1/2)*x+1/x-10 = 0

1*x^-1 = 10 // : 1

x^-1 = 10

-1 < 0

1/(x^1) = 10 // * x^1

1 = 10*x^1 // : 10

1/10 = x^1

x = 1/10

x = 1/10

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