1/x+5/(x-2)=0

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Solution for 1/x+5/(x-2)=0 equation: 



1/x+5/(x-2)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x-2)!=0

We move all terms containing x to the left, all other terms to the right

x!=2

x∈R



We calculate fractions


(1*(x-2))/(x^2-2x)+5x/(x^2-2x)=0



We calculate terms in parentheses: +(1*(x-2))/(x^2-2x), so:

1*(x-2))/(x^2-2x

We add all the numbers together, and all the variables

-2x+1*(x-2))/(x^2

We multiply all the terms by the denominator


-2x*(x^2+1*(x-2))

Back to the equation:

+(-2x*(x^2+1*(x-2)))



We multiply all the terms by the denominator


((-2x*(x^2+1*(x-2))))*(x^2-2x)+5x=0



We calculate terms in parentheses: +((-2x*(x^2+1*(x-2))))*(x^2-2x), so:

(-2x*(x^2+1*(x-2))))*(x^2-2x

We add all the numbers together, and all the variables

-2x+(-2x*(x^2+1*(x-2))))*(x^2

Back to the equation:

+(-2x+(-2x*(x^2+1*(x-2))))*(x^2)



We add all the numbers together, and all the variables

5x+(-2x+(-2x*(x^2+1*(x-2))))*x^2=0

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