1/x+5/(x-9)=0

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Solution for 1/x+5/(x-9)=0 equation: 



1/x+5/(x-9)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x-9)!=0

We move all terms containing x to the left, all other terms to the right

x!=9

x∈R



We calculate fractions


(1*(x-9))/(x^2-9x)+5x/(x^2-9x)=0



We calculate terms in parentheses: +(1*(x-9))/(x^2-9x), so:

1*(x-9))/(x^2-9x

We add all the numbers together, and all the variables

-9x+1*(x-9))/(x^2

We multiply all the terms by the denominator


-9x*(x^2+1*(x-9))

Back to the equation:

+(-9x*(x^2+1*(x-9)))



We multiply all the terms by the denominator


((-9x*(x^2+1*(x-9))))*(x^2-9x)+5x=0



We calculate terms in parentheses: +((-9x*(x^2+1*(x-9))))*(x^2-9x), so:

(-9x*(x^2+1*(x-9))))*(x^2-9x

We add all the numbers together, and all the variables

-9x+(-9x*(x^2+1*(x-9))))*(x^2

Back to the equation:

+(-9x+(-9x*(x^2+1*(x-9))))*(x^2)



We add all the numbers together, and all the variables

5x+(-9x+(-9x*(x^2+1*(x-9))))*x^2=0

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