1/x+5=x-4/x

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Solution for 1/x+5=x-4/x equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x+5 = x-(4/x) // - x-(4/x)

1/x-x+4/x+5 = 0

5*x^-1-1*x^1+5*x^0 = 0

(5*x^1-1*x^2+5*x^0)/(x^1) = 0 // * x^2

x^1*(5*x^1-1*x^2+5*x^0) = 0

x^1

5*x-x^2+5 = 0

5*x-x^2+5 = 0

DELTA = 5^2-(-1*4*5)

DELTA = 45

DELTA > 0

x = (45^(1/2)-5)/(-1*2) or x = (-45^(1/2)-5)/(-1*2)

x = (3*5^(1/2)-5)/(-2) or x = (-3*5^(1/2)-5)/(-2)

x in { (3*5^(1/2)-5)/(-2), (-3*5^(1/2)-5)/(-2)}

x in { (3*5^(1/2)-5)/(-2), (-3*5^(1/2)-5)/(-2) }

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