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1/x+7/5x=x+2/x
We move all terms to the left:
1/x+7/5x-(x+2/x)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/x+7/5x-(+x+2/x)=0
We get rid of parentheses
1/x+7/5x-x-2/x=0
We calculate fractions
-x+(-10x+1)/5x^2+7x/5x^2=0
We add all the numbers together, and all the variables
-1x+(-10x+1)/5x^2+7x/5x^2=0
We multiply all the terms by the denominator
-1x*5x^2+(-10x+1)+7x=0
We add all the numbers together, and all the variables
7x-1x*5x^2+(-10x+1)=0
Wy multiply elements
-5x^3+7x+(-10x+1)=0
We get rid of parentheses
-5x^3+7x-10x+1=0
We do not support expression: x^3
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