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1/x+8/(x+9)=1
We move all terms to the left:
1/x+8/(x+9)-(1)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (x+9)!=0We calculate fractions
We move all terms containing x to the left, all other terms to the right
x!=-9
x∈R
(1*(x+9))/(x^2+9x)+8x/(x^2+9x)-1=0
We calculate terms in parentheses: +(1*(x+9))/(x^2+9x), so:We multiply all the terms by the denominator
1*(x+9))/(x^2+9x
We add all the numbers together, and all the variables
9x+1*(x+9))/(x^2
We multiply all the terms by the denominator
9x*(x^2+1*(x+9))
Back to the equation:
+(9x*(x^2+1*(x+9)))
((9x*(x^2+1*(x+9))))*(x^2+9x)+8x-1*(x^2+9x)=0
We calculate terms in parentheses: +((9x*(x^2+1*(x+9))))*(x^2+9x), so:We add all the numbers together, and all the variables
(9x*(x^2+1*(x+9))))*(x^2+9x
We add all the numbers together, and all the variables
9x+(9x*(x^2+1*(x+9))))*(x^2
Back to the equation:
+(9x+(9x*(x^2+1*(x+9))))*(x^2)
8x+(9x+(9x*(x^2+1*(x+9))))*x^2-1*(x^2+9x)=0
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