1/x+8/(x+9)=1

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Solution for 1/x+8/(x+9)=1 equation:



1/x+8/(x+9)=1
We move all terms to the left:
1/x+8/(x+9)-(1)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (x+9)!=0
We move all terms containing x to the left, all other terms to the right
x!=-9
x∈R
We calculate fractions
(1*(x+9))/(x^2+9x)+8x/(x^2+9x)-1=0
We calculate terms in parentheses: +(1*(x+9))/(x^2+9x), so:
1*(x+9))/(x^2+9x
We add all the numbers together, and all the variables
9x+1*(x+9))/(x^2
We multiply all the terms by the denominator
9x*(x^2+1*(x+9))
Back to the equation:
+(9x*(x^2+1*(x+9)))
We multiply all the terms by the denominator
((9x*(x^2+1*(x+9))))*(x^2+9x)+8x-1*(x^2+9x)=0
We calculate terms in parentheses: +((9x*(x^2+1*(x+9))))*(x^2+9x), so:
(9x*(x^2+1*(x+9))))*(x^2+9x
We add all the numbers together, and all the variables
9x+(9x*(x^2+1*(x+9))))*(x^2
Back to the equation:
+(9x+(9x*(x^2+1*(x+9))))*(x^2)
We add all the numbers together, and all the variables
8x+(9x+(9x*(x^2+1*(x+9))))*x^2-1*(x^2+9x)=0

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