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1/x+x/(x+1)=1/x(x+1)
We move all terms to the left:
1/x+x/(x+1)-(1/x(x+1))=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (x+1)!=0
We move all terms containing x to the left, all other terms to the right
x!=-1
x∈R
Domain of the equation: x(x+1))!=0We calculate fractions
x∈R
We do not support expression: x^3
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