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1/x-1+2/2x-1=1+2
We move all terms to the left:
1/x-1+2/2x-1-(1+2)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
1/x+2/2x-1-1-3=0
We add all the numbers together, and all the variables
1/x+2/2x-5=0
We calculate fractions
2x/2x^2+2x/2x^2-5=0
We multiply all the terms by the denominator
2x+2x-5*2x^2=0
We add all the numbers together, and all the variables
4x-5*2x^2=0
Wy multiply elements
-10x^2+4x=0
a = -10; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-10)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-10}=\frac{-8}{-20} =2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-10}=\frac{0}{-20} =0 $
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