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1/x-1=4/5x
We move all terms to the left:
1/x-1-(4/5x)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/x-(+4/5x)-1=0
We get rid of parentheses
1/x-4/5x-1=0
We calculate fractions
5x/5x^2+(-4x)/5x^2-1=0
We multiply all the terms by the denominator
5x+(-4x)-1*5x^2=0
Wy multiply elements
-5x^2+5x+(-4x)=0
We get rid of parentheses
-5x^2+5x-4x=0
We add all the numbers together, and all the variables
-5x^2+x=0
a = -5; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-5)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-5}=\frac{-2}{-10} =1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-5}=\frac{0}{-10} =0 $
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