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1/x-3+1/3x-21=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
1/x+1/3x-24=0
We calculate fractions
3x/3x^2+x/3x^2-24=0
We multiply all the terms by the denominator
3x+x-24*3x^2=0
We add all the numbers together, and all the variables
4x-24*3x^2=0
Wy multiply elements
-72x^2+4x=0
a = -72; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·(-72)·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*-72}=\frac{-8}{-144} =1/18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*-72}=\frac{0}{-144} =0 $
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