1/x-3+1/x+5=x+1/x-3

Solution for 1/x-3+1/x+5=x+1/x-3 equation:

1/x-3+1/x+5=x+1/x-3

We move all terms to the left:

1/x-3+1/x+5-(x+1/x-3)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: x-3)!=0

x∈R


We add all the numbers together, and all the variables

1/x+1/x-(x+1/x-3)+2=0

We get rid of parentheses

1/x+1/x-x-1/x+3+2=0

We multiply all the terms by the denominator


-x*x+3*x+2*x+1+1-1=0

We add all the numbers together, and all the variables

5x-x*x+1=0

Wy multiply elements

-1x^2+5x+1=0

a = -1; b = 5; c = +1;
Δ = b2-4ac
Δ = 52-4·(-1)·1
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{29}}{2*-1}=\frac{-5-\sqrt{29}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{29}}{2*-1}=\frac{-5+\sqrt{29}}{-2}
$