1/x-3-1/x+6=0

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Solution for 1/x-3-1/x+6=0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x-(1/x)-3+6 = 0

1/x-x^-1-3+6 = 0

3 = 0

x belongs to the empty set

x belongs to the empty set

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