1/x-3-2/x+3=1/x(x)-9

Solution for 1/x-3-2/x+3=1/x(x)-9 equation:

1/x-3-2/x+3=1/x(x)-9

We move all terms to the left:

1/x-3-2/x+3-(1/x(x)-9)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: xx-9)!=0

x∈R


We add all the numbers together, and all the variables

1/x-2/x-(1/xx-9)=0

We get rid of parentheses

1/x-2/x-1/xx+9=0

We calculate fractions


(-2x+1)/x^2+(-x)/x^2+9=0

We add all the numbers together, and all the variables

(-2x+1)/x^2+(-1x)/x^2+9=0

We multiply all the terms by the denominator


(-2x+1)+(-1x)+9*x^2=0

We add all the numbers together, and all the variables

9x^2+(-2x+1)+(-1x)=0

We get rid of parentheses

9x^2-2x-1x+1=0

We add all the numbers together, and all the variables

9x^2-3x+1=0

a = 9; b = -3; c = +1;
Δ = b2-4ac
Δ = -32-4·9·1
Δ = -27
Delta is less than zero, so there is no solution for the equation