1/x-3=x/4

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Solution for 1/x-3=x/4 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x-3 = x/4 // - x/4

1/x-(x/4)-3 = 0

1*x^-1-1/4*x^1-3*x^0 = 0

(1*x^0-1/4*x^2-3*x^1)/(x^1) = 0 // * x^2

x^1*(1*x^0-1/4*x^2-3*x^1) = 0

x^1

(-1/4)*x^2-3*x+1 = 0

(-1/4)*x^2-3*x+1 = 0

DELTA = (-3)^2-(1*4*(-1/4))

DELTA = 10

DELTA > 0

x = (10^(1/2)+3)/(2*(-1/4)) or x = (3-10^(1/2))/(2*(-1/4))

x = -2*(10^(1/2)+3) or x = -2*(3-10^(1/2))

x in { -2*(10^(1/2)+3), -2*(3-10^(1/2))} 

x in { -2*(10^(1/2)+3), -2*(3-10^(1/2)) }

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