1/x-x/(x+3)=-1

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Solution for 1/x-x/(x+3)=-1 equation: 



1/x-x/(x+3)=-1

We move all terms to the left:

1/x-x/(x+3)-(-1)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (x+3)!=0

We move all terms containing x to the left, all other terms to the right

x!=-3

x∈R



We add all the numbers together, and all the variables

1/x-x/(x+3)+1=0

We calculate fractions


(-1x^2)/(x^2+3x)+(1*(x+3))/(x^2+3x)+1=0



We calculate terms in parentheses: +(1*(x+3))/(x^2+3x), so:

1*(x+3))/(x^2+3x

We add all the numbers together, and all the variables

3x+1*(x+3))/(x^2

We multiply all the terms by the denominator


3x*(x^2+1*(x+3))

Back to the equation:

+(3x*(x^2+1*(x+3)))



We multiply all the terms by the denominator


(-1x^2)+((3x*(x^2+1*(x+3))))*(x^2+3x)+1*(x^2+3x)=0



We calculate terms in parentheses: +((3x*(x^2+1*(x+3))))*(x^2+3x), so:

(3x*(x^2+1*(x+3))))*(x^2+3x

We add all the numbers together, and all the variables

3x+(3x*(x^2+1*(x+3))))*(x^2

Back to the equation:

+(3x+(3x*(x^2+1*(x+3))))*(x^2)



We get rid of parentheses

-1x^2+(3x+(3x*(x^2+1*(x+3))))*x^2+1*(x^2+3x)=0

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