1/x=(x)/(3x+18)

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Solution for 1/x=(x)/(3x+18) equation:


D( x )

x = 0

3*x+18 = 0

x = 0

x = 0

3*x+18 = 0

3*x+18 = 0

3*x+18 = 0 // - 18

3*x = -18 // : 3

x = -18/3

x = -6

x in (-oo:-6) U (-6:0) U (0:+oo)

1/x = x/(3*x+18) // - x/(3*x+18)

1/x-(x/(3*x+18)) = 0

(-1*x)/(3*x+18)+1/x = 0

(-1*x^2)/(x*(3*x+18))+(1*(3*x+18))/(x*(3*x+18)) = 0

1*(3*x+18)-1*x^2 = 0

3*x-x^2+18 = 0

3*x-x^2+18 = 0

3*x-x^2+18 = 0

DELTA = 3^2-(-1*4*18)

DELTA = 81

DELTA > 0

x = (81^(1/2)-3)/(-1*2) or x = (-81^(1/2)-3)/(-1*2)

x = -3 or x = 6

(x+3)*(x-6) = 0

((x+3)*(x-6))/(x*(3*x+18)) = 0

((x+3)*(x-6))/(x*(3*x+18)) = 0 // * x*(3*x+18)

(x+3)*(x-6) = 0

( x+3 )

x+3 = 0 // - 3

x = -3

( x-6 )

x-6 = 0 // + 6

x = 6

x in { -3, 6 }

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