1/x=0,02x

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Solution for 1/x=0,02x equation:



1/x=0.02x
We move all terms to the left:
1/x-(0.02x)=0
Domain of the equation: x!=0
x∈R
We add all the numbers together, and all the variables
1/x-(+0.02x)=0
We get rid of parentheses
1/x-0.02x=0
We multiply all the terms by the denominator
-(0.02x)*x+1=0
We add all the numbers together, and all the variables
-(+0.02x)*x+1=0
We multiply parentheses
-0x^2+1=0
We add all the numbers together, and all the variables
-1x^2+1=0
a = -1; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-1)·1
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2}{2*-1}=\frac{-2}{-2} =1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2}{2*-1}=\frac{2}{-2} =-1 $

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