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1/x=1+x
We move all terms to the left:
1/x-(1+x)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
1/x-(x+1)=0
We get rid of parentheses
1/x-x-1=0
We multiply all the terms by the denominator
-x*x-1*x+1=0
We add all the numbers together, and all the variables
-1x-x*x+1=0
Wy multiply elements
-1x^2-1x+1=0
a = -1; b = -1; c = +1;
Δ = b2-4ac
Δ = -12-4·(-1)·1
Δ = 5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{5}}{2*-1}=\frac{1-\sqrt{5}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{5}}{2*-1}=\frac{1+\sqrt{5}}{-2} $
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