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1/x=14/5x+9
We move all terms to the left:
1/x-(14/5x+9)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 5x+9)!=0We get rid of parentheses
x∈R
1/x-14/5x-9=0
We calculate fractions
5x/5x^2+(-14x)/5x^2-9=0
We multiply all the terms by the denominator
5x+(-14x)-9*5x^2=0
Wy multiply elements
-45x^2+5x+(-14x)=0
We get rid of parentheses
-45x^2+5x-14x=0
We add all the numbers together, and all the variables
-45x^2-9x=0
a = -45; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·(-45)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*-45}=\frac{0}{-90} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*-45}=\frac{18}{-90} =-1/5 $
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