1/y+1/(y+2)=1/3

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Solution for 1/y+1/(y+2)=1/3 equation: 


D( y )

y = 0

y+2 = 0

y = 0

y = 0

y+2 = 0

y+2 = 0

y+2 = 0 // - 2

y = -2

y in (-oo:-2) U (-2:0) U (0:+oo)

1/(y+2)+1/y = 1/3 // - 1/3

1/(y+2)+1/y-(1/3) = 0

1/(y+2)+1/y-1/3 = 0

(1*3*y)/(3*y*(y+2))+(1*3*(y+2))/(3*y*(y+2))+(-1*y*(y+2))/(3*y*(y+2)) = 0

1*3*(y+2)-1*y*(y+2)+1*3*y = 0

6*y-y^2-2*y+6 = 0

4*y-y^2+6 = 0

4*y-y^2+6 = 0

4*y-y^2+6 = 0

DELTA = 4^2-(-1*4*6)

DELTA = 40

DELTA > 0

y = (40^(1/2)-4)/(-1*2) or y = (-40^(1/2)-4)/(-1*2)

y = (2*10^(1/2)-4)/(-2) or y = (-2*10^(1/2)-4)/(-2)

(y-((2*10^(1/2)-4)/(-2)))*(y-((-2*10^(1/2)-4)/(-2))) = 0

((y-((2*10^(1/2)-4)/(-2)))*(y-((-2*10^(1/2)-4)/(-2))))/(3*y*(y+2)) = 0

((y-((2*10^(1/2)-4)/(-2)))*(y-((-2*10^(1/2)-4)/(-2))))/(3*y*(y+2)) = 0 // * 3*y*(y+2)

(y-((2*10^(1/2)-4)/(-2)))*(y-((-2*10^(1/2)-4)/(-2))) = 0

( y-((-2*10^(1/2)-4)/(-2)) )

y-((-2*10^(1/2)-4)/(-2)) = 0 // + (-2*10^(1/2)-4)/(-2)

y = (-2*10^(1/2)-4)/(-2)

( y-((2*10^(1/2)-4)/(-2)) )

y-((2*10^(1/2)-4)/(-2)) = 0 // + (2*10^(1/2)-4)/(-2)

y = (2*10^(1/2)-4)/(-2)

y in { (-2*10^(1/2)-4)/(-2), (2*10^(1/2)-4)/(-2) }

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