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1/y+1=1/6y
We move all terms to the left:
1/y+1-(1/6y)=0
Domain of the equation: y!=0
y∈R
Domain of the equation: 6y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
1/y-(+1/6y)+1=0
We get rid of parentheses
1/y-1/6y+1=0
We calculate fractions
6y/6y^2+(-y)/6y^2+1=0
We add all the numbers together, and all the variables
6y/6y^2+(-1y)/6y^2+1=0
We multiply all the terms by the denominator
6y+(-1y)+1*6y^2=0
Wy multiply elements
6y^2+6y+(-1y)=0
We get rid of parentheses
6y^2+6y-1y=0
We add all the numbers together, and all the variables
6y^2+5y=0
a = 6; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·6·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*6}=\frac{-10}{12} =-5/6 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*6}=\frac{0}{12} =0 $
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