1/y+2=12

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Solution for 1/y+2=12 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

1/y+2 = 12 // - 12

1/y-12+2 = 0

1*y^-1 = 10 // : 1

y^-1 = 10

-1 < 0

1/(y^1) = 10 // * y^1

1 = 10*y^1 // : 10

1/10 = y^1

y = 1/10

y = 1/10

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