1/y+3/5=8/5y

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Solution for 1/y+3/5=8/5y equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

1/y+3/5 = (8/5)*y // - (8/5)*y

1/y-((8/5)*y)+3/5 = 0

(-8/5)*y+1/y+3/5 = 0

1*y^-1-8/5*y^1+3/5*y^0 = 0

(3/5*y^1-8/5*y^2+1*y^0)/(y^1) = 0 // * y^2

y^1*(3/5*y^1-8/5*y^2+1*y^0) = 0

y^1

(-8/5)*y^2+(3/5)*y+1 = 0

(-8/5)*y^2+(3/5)*y+1 = 0

DELTA = (3/5)^2-(1*4*(-8/5))

DELTA = 169/25

DELTA > 0

y = ((169/25)^(1/2)-(3/5))/(2*(-8/5)) or y = (-(3/5)-(169/25)^(1/2))/(2*(-8/5))

y = -5/8 or y = 1

y in { -5/8, 1} 

y in { -5/8, 1 }

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