1/y+7/3=-1/2y

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Solution for 1/y+7/3=-1/2y equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

1/y+7/3 = (-1/2)*y // - (-1/2)*y

1/y-((-1/2)*y)+7/3 = 0

(1/2)*y+1/y+7/3 = 0

1/2*y^1+1*y^-1+7/3*y^0 = 0

(1/2*y^2+7/3*y^1+1*y^0)/(y^1) = 0 // * y^2

y^1*(1/2*y^2+7/3*y^1+1*y^0) = 0

y^1

(1/2)*y^2+(7/3)*y+1 = 0

(1/2)*y^2+(7/3)*y+1 = 0

DELTA = (7/3)^2-(1*4*(1/2))

DELTA = 31/9

DELTA > 0

y = ((31/9)^(1/2)-(7/3))/(2*(1/2)) or y = (-(7/3)-(31/9)^(1/2))/(2*(1/2))

y = (31/9)^(1/2)-7/3 or y = -((31/9)^(1/2)+7/3)

y in { -((31/9)^(1/2)+7/3), (31/9)^(1/2)-7/3} 

y in { -((31/9)^(1/2)+7/3), (31/9)^(1/2)-7/3 }

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