1/y-1/2y-1/5y=10/y+1

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Solution for 1/y-1/2y-1/5y=10/y+1 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

1/y-((1/2)*y)-((1/5)*y) = 10/y+1 // - 10/y+1

1/y-((1/2)*y)-((1/5)*y)-(10/y)-1 = 0

(-1/2)*y+(-1/5)*y+1/y-10*y^-1-1 = 0

-7/10*y^1-9*y^-1-1*y^0 = 0

(-7/10*y^2-1*y^1-9*y^0)/(y^1) = 0 // * y^2

y^1*(-7/10*y^2-1*y^1-9*y^0) = 0

y^1

(-7/10)*y^2-y-9 = 0

(-7/10)*y^2-y-9 = 0

DELTA = (-1)^2-(-9*4*(-7/10))

DELTA = -121/5

DELTA < 0

y in { } 

y belongs to the empty set

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