1/y=(2/x)-(3/5)

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Solution for 1/y=(2/x)-(3/5) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/y = 2/x-(3/5) // - 2/x-(3/5)

1/y-(2/x)+3/5 = 0

1/y-2*x^-1+3/5 = 0

-2*x^-1 = -(y^-1+3/5) // : -2

x^-1 = (y^-1+3/5)/2

-1 < 0

1/(x^1) = (y^-1+3/5)/2 // * x^1

1 = x^1*((y^-1+3/5)/2) // : (y^-1+3/5)/2

2*(y^-1+3/5)^-1 = x^1

x = 2*(y^-1+3/5)^-1

x = 2*(y^-1+3/5)^-1

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