1/y=(y+2/2y)

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Solution for 1/y=(y+2/2y) equation: 



1/y=(y+2/2y)

We move all terms to the left:

1/y-((y+2/2y))=0



Domain of the equation: y!=0

y∈R





Domain of the equation: 2y))!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

1/y-((+y+2/2y))=0

We calculate fractions


2y/2y^2+(-((+y+2*y)/2y^2=0

We add all the numbers together, and all the variables

2y/2y^2+(-((+3y)/2y^2=0

We multiply all the terms by the denominator


2y+(-((+3y)=0



We calculate terms in parentheses: +(-((+3y), so:

-((+3y





We calculate terms in parentheses: +(-((+3y), so:

-((+3y





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-((+3y





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-((+3y





We calculate terms in parentheses: +(-((+3y), so:

-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





We calculate terms in parentheses: +(-((+3y), so:

-((+3y





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-((+3y





We calculate terms in parentheses: +(-((+3y), so:

-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





We calculate terms in parentheses: +(-((+3y), so:

-((+3y





We calculate terms in parentheses: +(-((+3y), so:

-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





We calculate terms in parentheses: +(-((+3y), so:

-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y





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-((+3y

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