1/y=8-3/y

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Solution for 1/y=8-3/y equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

1/y = 8-(3/y) // - 8-(3/y)

1/y+3/y-8 = 0

4*y^-1 = 8 // : 4

y^-1 = 2

-1 < 0

1/(y^1) = 2 // * y^1

1 = 2*y^1 // : 2

1/2 = y^1

y = 1/2

y = 1/2

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