1/z+8*4z+32/z+3

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Solution for 1/z+8*4z+32/z+3 equation:


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

4*8*z+1/z+32/z+3 = 0

32*z^1+33*z^-1+3*z^0 = 0

(32*z^2+3*z^1+33*z^0)/(z^1) = 0 // * z^2

z^1*(32*z^2+3*z^1+33*z^0) = 0

z^1

32*z^2+3*z+33 = 0

32*z^2+3*z+33 = 0

DELTA = 3^2-(4*32*33)

DELTA = -4215

DELTA < 0

z in { }

z belongs to the empty set

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