1/z-1/2z-1/5z=10/z

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Solution for 1/z-1/2z-1/5z=10/z equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

1/z-((1/2)*z)-((1/5)*z) = 10/z // - 10/z

1/z-((1/2)*z)-((1/5)*z)-(10/z) = 0

(-1/2)*z+(-1/5)*z+1/z-10*z^-1 = 0

-7/10*z^1-9*z^-1 = 0

(-7/10*z^2-9*z^0)/(z^1) = 0 // * z^2

z^1*(-7/10*z^2-9*z^0) = 0

z^1

(-7/10)*z^2-9 = 0

(-7/10)*z^2-9 = 0

DELTA = 0^2-(-9*4*(-7/10))

DELTA = -126/5

DELTA < 0

z in { } 

z belongs to the empty set

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