1/z-1/5z-1/4z=20/z+1

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Solution for 1/z-1/5z-1/4z=20/z+1 equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

1/z-((1/5)*z)-((1/4)*z) = 20/z+1 // - 20/z+1

1/z-((1/5)*z)-((1/4)*z)-(20/z)-1 = 0

(-1/5)*z+(-1/4)*z+1/z-20*z^-1-1 = 0

-9/20*z^1-19*z^-1-1*z^0 = 0

(-9/20*z^2-1*z^1-19*z^0)/(z^1) = 0 // * z^2

z^1*(-9/20*z^2-1*z^1-19*z^0) = 0

z^1

(-9/20)*z^2-z-19 = 0

(-9/20)*z^2-z-19 = 0

DELTA = (-1)^2-(-19*4*(-9/20))

DELTA = -166/5

DELTA < 0

z in { } 

z belongs to the empty set

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