1/z=(5/z)-1/2

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Solution for 1/z=(5/z)-1/2 equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

1/z = 5/z-(1/2) // - 5/z-(1/2)

1/z-(5/z)+1/2 = 0

1/z-5*z^-1+1/2 = 0

-4*z^-1 = -1/2 // : -4

z^-1 = 1/8

-1 < 0

1/(z^1) = 1/8 // * z^1

1 = 1/8*z^1 // : 1/8

8 = z^1

z = 8

z = 8

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