1/z=1/x+1/y

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Solution for 1/z=1/x+1/y equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/z = 1/x+1/y // - 1/x+1/y

1/z-(1/x)-(1/y) = 0

1/z-x^-1-y^-1 = 0

-1*x^-1 = -(z^-1-y^-1) // : -1

x^-1 = z^-1-y^-1

-1 < 0

1/(x^1) = z^-1-y^-1 // * x^1

1 = x^1*(z^-1-y^-1) // : z^-1-y^-1

1/(z^-1-y^-1) = x^1

x = 1/(z^-1-y^-1)

x = 1/(z^-1-y^-1)

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