10(-13-z)+10=-2(7z+32)

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Solution for 10(-13-z)+10=-2(7z+32) equation:



10(-13-z)+10=-2(7z+32)
We move all terms to the left:
10(-13-z)+10-(-2(7z+32))=0
We add all the numbers together, and all the variables
10(-1z-13)-(-2(7z+32))+10=0
We multiply parentheses
-10z-(-2(7z+32))-130+10=0
We calculate terms in parentheses: -(-2(7z+32)), so:
-2(7z+32)
We multiply parentheses
-14z-64
Back to the equation:
-(-14z-64)
We add all the numbers together, and all the variables
-10z-(-14z-64)-120=0
We get rid of parentheses
-10z+14z+64-120=0
We add all the numbers together, and all the variables
4z-56=0
We move all terms containing z to the left, all other terms to the right
4z=56
z=56/4
z=14

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