10(-2-3y)+8y=-20

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Solution for 10(-2-3y)+8y=-20 equation: 



10(-2-3y)+8y=-20

We move all terms to the left:

10(-2-3y)+8y-(-20)=0

We add all the numbers together, and all the variables

10(-3y-2)+8y-(-20)=0

We add all the numbers together, and all the variables

8y+10(-3y-2)+20=0

We multiply parentheses

8y-30y-20+20=0

We add all the numbers together, and all the variables

-22y=0

y=0/-22

y=0

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