10(-3-2t)+10=2(6t-13)

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Solution for 10(-3-2t)+10=2(6t-13) equation: 



10(-3-2t)+10=2(6t-13)

We move all terms to the left:

10(-3-2t)+10-(2(6t-13))=0

We add all the numbers together, and all the variables

10(-2t-3)-(2(6t-13))+10=0

We multiply parentheses

-20t-(2(6t-13))-30+10=0



We calculate terms in parentheses: -(2(6t-13)), so:

2(6t-13)

We multiply parentheses

12t-26

Back to the equation:

-(12t-26)



We add all the numbers together, and all the variables

-20t-(12t-26)-20=0

We get rid of parentheses

-20t-12t+26-20=0

We add all the numbers together, and all the variables

-32t+6=0

We move all terms containing t to the left, all other terms to the right

-32t=-6

t=-6/-32

t=3/16

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