10(-3/4)+7z=3

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Solution for 10(-3/4)+7z=3 equation: 



10(-3/4)+7z=3

We move all terms to the left:

10(-3/4)+7z-(3)=0

determiningTheFunctionDomain
7z-3+10(-3/4)=0

We multiply parentheses

7z-3-3/4*10=0

We multiply all the terms by the denominator


7z*4*10-3-3*4*10=0

We add all the numbers together, and all the variables

7z*4*10-123=0

Wy multiply elements

280z*1-123=0

Wy multiply elements

280z-123=0

We move all terms containing z to the left, all other terms to the right

280z=123

z=123/280

z=123/280

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