10(-3x+1)=-14(x+2)+38-16x

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Solution for 10(-3x+1)=-14(x+2)+38-16x equation: 



10(-3x+1)=-14(x+2)+38-16x

We move all terms to the left:

10(-3x+1)-(-14(x+2)+38-16x)=0

We multiply parentheses

-30x-(-14(x+2)+38-16x)+10=0



We calculate terms in parentheses: -(-14(x+2)+38-16x), so:

-14(x+2)+38-16x

determiningTheFunctionDomain
-14(x+2)-16x+38

We add all the numbers together, and all the variables

-16x-14(x+2)+38

We multiply parentheses

-16x-14x-28+38

We add all the numbers together, and all the variables

-30x+10

Back to the equation:

-(-30x+10)



We get rid of parentheses

-30x+30x-10+10=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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