10(-4x+4)=20x(1-4x)

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Solution for 10(-4x+4)=20x(1-4x) equation: 



10(-4x+4)=20x(1-4x)

We move all terms to the left:

10(-4x+4)-(20x(1-4x))=0

We add all the numbers together, and all the variables

10(-4x+4)-(20x(-4x+1))=0

We multiply parentheses

-40x-(20x(-4x+1))+40=0



We calculate terms in parentheses: -(20x(-4x+1)), so:

20x(-4x+1)

We multiply parentheses

-80x^2+20x

Back to the equation:

-(-80x^2+20x)



We get rid of parentheses

80x^2-20x-40x+40=0

We add all the numbers together, and all the variables

80x^2-60x+40=0

a = 80; b = -60; c = +40;
Δ = b2-4ac
Δ = -602-4·80·40
Δ = -9200
Delta is less than zero, so there is no solution for the equation

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