10(-b-2)+2(8+9b)=9b-1+b-9

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Solution for 10(-b-2)+2(8+9b)=9b-1+b-9 equation: 



10(-b-2)+2(8+9b)=9b-1+b-9

We move all terms to the left:

10(-b-2)+2(8+9b)-(9b-1+b-9)=0

We add all the numbers together, and all the variables

10(-1b-2)+2(9b+8)-(10b-10)=0

We multiply parentheses

-10b+18b-(10b-10)-20+16=0

We get rid of parentheses

-10b+18b-10b+10-20+16=0

We add all the numbers together, and all the variables

-2b+6=0

We move all terms containing b to the left, all other terms to the right

-2b=-6

b=-6/-2

b=+3

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