10(1+3b)-2=98

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Solution for 10(1+3b)-2=98 equation: 



10(1+3b)-2=98

We move all terms to the left:

10(1+3b)-2-(98)=0

We add all the numbers together, and all the variables

10(3b+1)-2-98=0

We add all the numbers together, and all the variables

10(3b+1)-100=0

We multiply parentheses

30b+10-100=0

We add all the numbers together, and all the variables

30b-90=0

We move all terms containing b to the left, all other terms to the right

30b=90

b=90/30

b=3

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