10(1+3b)=-23+3b

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Solution for 10(1+3b)=-23+3b equation: 



10(1+3b)=-23+3b

We move all terms to the left:

10(1+3b)-(-23+3b)=0

We add all the numbers together, and all the variables

10(3b+1)-(3b-23)=0

We multiply parentheses

30b-(3b-23)+10=0

We get rid of parentheses

30b-3b+23+10=0

We add all the numbers together, and all the variables

27b+33=0

We move all terms containing b to the left, all other terms to the right

27b=-33

b=-33/27

b=-1+2/9

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