10(1+3b)=-23-3b

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Solution for 10(1+3b)=-23-3b equation: 



10(1+3b)=-23-3b

We move all terms to the left:

10(1+3b)-(-23-3b)=0

We add all the numbers together, and all the variables

10(3b+1)-(-3b-23)=0

We multiply parentheses

30b-(-3b-23)+10=0

We get rid of parentheses

30b+3b+23+10=0

We add all the numbers together, and all the variables

33b+33=0

We move all terms containing b to the left, all other terms to the right

33b=-33

b=-33/33

b=-1

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