10(1+3v)=-8(6v+1)

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Solution for 10(1+3v)=-8(6v+1) equation: 



10(1+3v)=-8(6v+1)

We move all terms to the left:

10(1+3v)-(-8(6v+1))=0

We add all the numbers together, and all the variables

10(3v+1)-(-8(6v+1))=0

We multiply parentheses

30v-(-8(6v+1))+10=0



We calculate terms in parentheses: -(-8(6v+1)), so:

-8(6v+1)

We multiply parentheses

-48v-8

Back to the equation:

-(-48v-8)



We get rid of parentheses

30v+48v+8+10=0

We add all the numbers together, and all the variables

78v+18=0

We move all terms containing v to the left, all other terms to the right

78v=-18

v=-18/78

v=-3/13

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