10(1-2x)+6=-3-3(1+3x)

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Solution for 10(1-2x)+6=-3-3(1+3x) equation: 



10(1-2x)+6=-3-3(1+3x)

We move all terms to the left:

10(1-2x)+6-(-3-3(1+3x))=0

We add all the numbers together, and all the variables

10(-2x+1)-(-3-3(3x+1))+6=0

We multiply parentheses

-20x-(-3-3(3x+1))+10+6=0



We calculate terms in parentheses: -(-3-3(3x+1)), so:

-3-3(3x+1)

determiningTheFunctionDomain
-3(3x+1)-3

We multiply parentheses

-9x-3-3

We add all the numbers together, and all the variables

-9x-6

Back to the equation:

-(-9x-6)



We add all the numbers together, and all the variables

-20x-(-9x-6)+16=0

We get rid of parentheses

-20x+9x+6+16=0

We add all the numbers together, and all the variables

-11x+22=0

We move all terms containing x to the left, all other terms to the right

-11x=-22

x=-22/-11

x=+2

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