10(1-2x)+6=-3-3(1+3x)

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Solution for 10(1-2x)+6=-3-3(1+3x) equation:



10(1-2x)+6=-3-3(1+3x)
We move all terms to the left:
10(1-2x)+6-(-3-3(1+3x))=0
We add all the numbers together, and all the variables
10(-2x+1)-(-3-3(3x+1))+6=0
We multiply parentheses
-20x-(-3-3(3x+1))+10+6=0
We calculate terms in parentheses: -(-3-3(3x+1)), so:
-3-3(3x+1)
determiningTheFunctionDomain -3(3x+1)-3
We multiply parentheses
-9x-3-3
We add all the numbers together, and all the variables
-9x-6
Back to the equation:
-(-9x-6)
We add all the numbers together, and all the variables
-20x-(-9x-6)+16=0
We get rid of parentheses
-20x+9x+6+16=0
We add all the numbers together, and all the variables
-11x+22=0
We move all terms containing x to the left, all other terms to the right
-11x=-22
x=-22/-11
x=+2

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