10(1-3b)+2=-18

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Solution for 10(1-3b)+2=-18 equation: 



10(1-3b)+2=-18

We move all terms to the left:

10(1-3b)+2-(-18)=0

We add all the numbers together, and all the variables

10(-3b+1)+2-(-18)=0

We add all the numbers together, and all the variables

10(-3b+1)+20=0

We multiply parentheses

-30b+10+20=0

We add all the numbers together, and all the variables

-30b+30=0

We move all terms containing b to the left, all other terms to the right

-30b=-30

b=-30/-30

b=1

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