10(1/2x+2)-5=(x-6)+1

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Solution for 10(1/2x+2)-5=(x-6)+1 equation: 



10(1/2x+2)-5=(x-6)+1

We move all terms to the left:

10(1/2x+2)-5-((x-6)+1)=0



Domain of the equation: 2x+2)!=0

x∈R



We multiply parentheses

10x-((x-6)+1)+20-5=0



We calculate terms in parentheses: -((x-6)+1), so:

(x-6)+1

We get rid of parentheses

x-6+1

We add all the numbers together, and all the variables

x-5

Back to the equation:

-(x-5)



We add all the numbers together, and all the variables

10x-(x-5)+15=0

We get rid of parentheses

10x-x+5+15=0

We add all the numbers together, and all the variables

9x+20=0

We move all terms containing x to the left, all other terms to the right

9x=-20

x=-20/9

x=-2+2/9

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